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• #### Sums and products in finite fields: an integral geometric viewpoint ﻿

(2007)
We prove that if $A \subset {\Bbb F}_q$ is such that $|A|>q^{{1/2}+\frac{1}{2d}},$ then ${\Bbb F}_q^{*} \subset dA^2=A^2+...+A^2 d \text{times},$ where $A^2=\{a \cdot a': a,a' \in A\},$ and where ${\Bbb F}_q^{*}$ ...